10=(3^x+5)-2

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Solution for 10=(3^x+5)-2 equation: 



10=(3^x+5)-2

We move all terms to the left:

10-((3^x+5)-2)=0



We calculate terms in parentheses: -((3^x+5)-2), so:

(3^x+5)-2

We get rid of parentheses

3^x+5-2

We add all the numbers together, and all the variables

3^x+3

Back to the equation:

-(3^x+3)



We get rid of parentheses

-3^x-3+10=0

We add all the numbers together, and all the variables

-3^x+7=0

We move all terms containing x to the left, all other terms to the right

-3^x=-7

x=-7/1

x=-7

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